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weqwewe [10]
3 years ago
7

Dilations on coordinate plane algebraic representation

Mathematics
1 answer:
igomit [66]3 years ago
8 0

Answer:

When a dilation in the coordinate plane has the origin as the center of dilation, you can find points on the dilated image by multiplying the x- and y-coordinates of the original figure by the scale factor. For scale factor k, the algebraic representation of the dilation is (x, y) → (kx, ky)

Step-by-step explanation:

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Which number is equivalent to 4 /12
Shkiper50 [21]

Step-by-step explanation:

a 9/2 is the correct answer.

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The radius of a circle is 10 m. Find its area to the nearest whole number.
Bess [88]
<h3>given:</h3>

radius= 10 m

<h3>to find:</h3>

the area of the given circle.

<h3>solution:</h3>

a = \pi {r}^{2}

a = \pi \times  {10}^{2}

a = 314.15927 \:  {m}^{2}

a = 314 \:  {m}^{2}

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>circle</u><u> </u><u>is</u><u> </u><u>3</u><u>1</u><u>4</u><u> </u><u>square</u><u> </u><u>meters</u><u>. </u>

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2 years ago
A company that makes and sells mini action-figures uses cubic cardboard boxes with a side length of 2 inches to package the acti
Ksivusya [100]

Answer:

480

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3 0
1 year ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

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1 year ago
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D, keep change flip
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Change: division to multiplication
Flip: 9/5 to 5/9
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