2 years ago

N+2=-14-n Solving equations with variables on both sides

Mathematics

1 answer:

Dafna11 [192]2 years ago

4 0

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

$\qquad \sf \dashrightarrow \: n + 2 = - 14 - n$

$\qquad \sf \dashrightarrow \: n + n = - 14 - 2$

$\qquad \sf \dashrightarrow \: 2n = - 16$

$\qquad \sf \dashrightarrow \: n = - 16 \div 2$

$\qquad \sf \dashrightarrow \: n = - 8$

Required value of n = -8

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assume the age of night school students is normally distributed. A simple random sample of 24 night school students had an avera

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Let
n = number of data
s = standard deviation (sample)
S = standard deviation (population)

The working equations is

$\frac{(n-1) s^{2} }{ x^{2}_{right} } \ \textless \ S^{2} \ \textless \ \frac{(n-1) s^{2} }{ x^{2}_{left} }$

To find $x^{2}_{right}$ , : (1 - 0.90)/2 = 0.05

To find $x^{2}_{left}$ , : 1 - 0.05 = 0.95

Degrees of freedom = n-1 = 24 - 1 = 23

This is shown in the figure attached. Since there is no row for df=23, we interpolate. Thus,

$x^{2}_{left} = 13.093$

$x^{2}_{right} = 35.17$

Substitute all values,

$\frac{(24-1) 5.6^{2} }{ 35.17} \ \textless \ S^{2} \ \textless \ \frac{(24-1) 5.6^{2} }{ 13.093} }$

Thus the answer is,

$20.51\ \textless \ S^{2} \ \textless \ 55.09$