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yarga [219]
4 years ago
11

What is the decimal form or 100/3, 100/5, 100/6? Determine whether each decimal repeats or terminates.

Mathematics
1 answer:
BartSMP [9]4 years ago
3 0

Answer:

100/3=33.33333

100/5=20

100/6=16.66666666

Step-by-step explanation:

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Misaki cut some wood for a bookcase she is building.She needs to find how many 1/3 ft boards she can make from a 5 ft board.Expl
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Answer: There are 15 boards that she can make from a 5 ft board.

Step-by-step explanation:

Since we have given that

Length of a board = 5 ft

Length of board she can make from the above board is given by

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We need to find the number of boards she can make from a 5 ft board.

According to question,

\text{Number of boards}=\frac{5}{\frac{1}{3}}\\\\\text{Number of boards}=5\times 3\\\\\text{Number of boards}=15

Hence, there are 15 boards that she can make from a 5 ft board.

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3 years ago
Which equation represents the magnitude of an
Basile [38]

Answer:

M=\log{(100S)}

Step-by-step explanation:

The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).

How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say 10^m=S, which we can rewrite in logarithmic form as m=\log{S}.

We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation

M=\log{(100S)}.

To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so 3=\log{S}. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation M=\log{(100S)} using the product rule for logarithms to get the equation

M=\log{(100S)}=\log{100}+\log{S}

And using the fact that \log{100}=2 and our assumption that \log{S}=3, we see that M=2+3=5 as we wanted.

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How many thousands are there in each of the following 14060. Thosands<br>​
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14.06 thousands.

Step-by-step explanation:

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