3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
Answer:
x is less than 4
or
x is greater than 4
Step-by-step explanation:
-5x < -15x + 40 -5x < -15x + 40
+15x +15x -40 -40
10x < 40 -40 - 5x < -15x
÷10 ÷10 +5x +5x
× < 4 -40 < -10x
÷10 ÷10
4 < ×
I think it’s what ever you have left after paying, I’m sorry if this is wrong.
Answer:
(A) T-stat = 1.82
(B) Critical value is 1.645
(C) Yes, there is sufficient evidence to reject the null hypothesis using a 0.05 significance level.
Step-by-step explanation:
(A) T-stat (z) = (sample mean - population mean) ÷ sd/√n
sample mean = 3850 bus miles
population mean = 3800 bus miles
sd = 275 bus miles
n = 100
z = (3850 - 3800) ÷ 275/√100 = 50 ÷ 275/10 = 50 ÷ 27.5 = 1.82
(B) The test is a one-tailed test. The critical value is obtained from the standard normal distribution table. The critical value using a 0.05 significance level is 1.645
(C) Null hypothesis: The bus mechanical reliability is 3850 bus miles.
Alternate hypothesis: The bus mechanical reliability is less than 3850 bus miles.
Conclusion:
There is sufficient evidence to reject the null hypothesis because the test statistic (1.82) is greater than the critical value (1.645)
