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kirill [66]
2 years ago
9

Based on this, __electrons__________________ have almost no mass compared to the other particles.

Chemistry
1 answer:
Setler79 [48]2 years ago
7 0

Based on this, Individual electrons in graphene have almost no mass compared to the other particles.

The material graphene consists of a single layer of carbon atoms arranged in a hexagonal lattice.

Electrons flowing through graphene can be scattered from impurities (such as foreign atoms in the lattice), from other electrons and from lattice vibrations known as phonons.

What happens to the electrons in graphene?

According to the researchers, such high values are a result of the photo thermoelectric effect. “It turns out that when you shine a light on graphene, the electrons in the material heat up, and remain hot, while the underlying carbon lattice remains cool,”

Why are electrons massless in graphene?

Yes, low energy electrons and holes in graphene can be thought of as massless because of the linear dispersion of the band structure near the K points.

This is an analogy to the relativistic energy dispersion E2=P2C2+M2C4, which becomes linear in momentum for m=0.

To learn more about electrons here

brainly.com/question/12001116

#SPJ4

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Chemistry test bound theories
liq [111]

covalent bond is firmed between two atoms

5 0
3 years ago
Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1
NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x                       x               x

The dissociation constant from the above reactions is given by:

Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}

6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}

6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75    

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

\% = \frac{x}{[HCN]} \times 100

\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100

\% = 3.5 \cdot 10^{-3} \%          

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!      

6 0
3 years ago
Identify fossil types match each each type of fossil to its description
dem82 [27]
Well we need to see the fossil
4 0
3 years ago
Read 2 more answers
Identify this reaction <br> In pic
balu736 [363]

Answer:

Double displacement

Explanation:

5 0
3 years ago
Calculate the molarity when 14.6 g Ethanol (C2H5OH) is dissolved in a 2.10 L solution
fiasKO [112]

Answer:

0.15 M

Explanation:

14.6/46.07g/mol = 0.316 mol Ethanol.

0.316/2.1= 0.15 M

5 0
3 years ago
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