Answer:
The answer to your question is: Fluorine, Chlorine, Bromine, Iodine
Explanation:
Electron configuration ns² np⁵
We observe that this electron configuration finishes in "p". Elements from groups IIIA to VIIIA finish their electron configuration in "p".
Elements in Group IIIA finish in p¹
Group IVA finish in p²
Group VA finish in p³
Group VIA finish in p⁴
Group VIIA finish in p⁵
Group VIIIA finish in p⁶
Then, the list of elements with this electron configuration is:
Fluorine, Chlorine, Bromine, Iodine
2.22 g of NaF*1mol/41.97g of NaF =0.0529 moles
Answer:
0.60
Explanation:
pH = - log[H+]
[HCl] = [H+] = 0.25 M, because HCl is strong acid, so it dissociates completely.
PH = -log[0.25] = 0.60
Answer:
The answer to your question is b. Mg is being oxidized and c. Mg is the
reducing agent.
Explanation:
Reduction is the gain of electrons
Oxidation is the loss of electrons
Reducing agent is the element that oxidizes itself and reduces another element.
Oxidizing agent is the element the reduces itself and oxidizes another element.
In this reaction:
Magnesium loses electrons so it is being oxidized and it is the reducing agent.
Im pretty sure you do the number times the percentage converted to a decimal and then add the sums so (46*0.706)+(48*0.129)+(50*0.165)
32.476+6.192+8.25
=46.918 amu
*i dont trust my calc so pleasee check if the answer is right and also remember to convert a percent to decimal move the decimal back 2 places so like for 12.9% the decimal is gonna be 0.129
hope this helpss ask if you have questions