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nekit [7.7K]
2 years ago
6

imagine that the atom in drawing b had been removed by physical separation from one of the substances in model 1. what substance

s could have been the source of the atom in drawing b?
Chemistry
1 answer:
Kisachek [45]2 years ago
4 0

The substance that could have been the source of the atom is an element.

<h3>What is an element?</h3>

We know that an element is the smallest independent part of an substance . Given the fact that atoms are contained in elements, we know that if you open up an element, what you would find is an atom.

Looking at the models, what we can see in drawing 1 must be the element of the substance. The elements have independent existence as we can see.

If the implies that if the atom in drawing b had been removed by physical separation from one of the substances in model 1, the substance that could have been the source of the atom is an element.

Learn more about elements:brainly.com/question/13025901

#SPJ1

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Nearly every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element
baherus [9]

Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

Similarly, every compound of silicon has the element in the ⁺4 oxidation state. In contrast, most compounds of lead have the element in the ⁺2 state because of inert pair effect.

<h3>What is Inert pair effect? </h3>

The inert-pair effect is defined as the tendency of two electrons in the outermost atomic s-orbital almost remain unshared in the compounds of the post-transition metals.

<h3>How we calculate Oxidation state? </h3>
  • Each atom in an element either be in its uncombined or free state has oxidation number of zero. Such as each atom in H₂, Cl₂ , P4, ,O₂ , Na, Al, O3, S8, and Mg, all have an oxidation number zero.
  • The oxidation state of ions that comprise of only one atom is the actual charge on the ion.
  • The oxidation state of hydrogen is +1, excluding when it is bonded to metals having two elements. For example, CaH2, its oxidation state is –1.
  • Fluorine and other halogens have an oxidation state equal to –1 when they appear as a form of halide ions in their compounds.

Since the inert pair effect increases as we go down the group and become more predominant, therefore, the stability of +2 oxidation state goes on increasing down the group. Therefore, gallium, indium are mostly found in +1 oxidation state.

Thus, we concluded that Boron shows analogous behaviour with silicon. Every compound of Boron have +3 oxidation state, while as we go down the the oxidation state become +1 and +3. For example, gallium, indium, etc.

learn more about oxidation state:

brainly.com/question/25551544

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Round 2675 to two significant figures.
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An aluminum engine block has a volume of 4.77 L and a mass of 12.88 kg. what is the density of the aluminum in grams per cubic c
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12.88 x 1000 = 12,880 g

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D =  mass / volume

D = 12,880 / 4770

D = 2.70 g/cm³

hope this helps!
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