Answer:
The budgeted materials need in kg. in the first quarter is 90,000 kg
Explanation:
For computing the budgeted material needed in the first quarter, first we have to calculate the consumption of first and second quarters separately, so that we can arrive to a solution.
The consumption of first quarter = Budgeted production × required kg
= 45,000 × 2
= 90,000 kg
The consumption of second quarter = Budgeted production × required kg
= 30,000 × 2
= 60,000 kg
The ending raw material inventory = 30% of second quarter
= 30% × 60,000
= 18,000 kg
Now put the formula to find out the purchase amount. The formula is shown below:
Raw material consumption = Opening raw material inventory + purchase of raw material - ending raw material inventory
where,
beginning inventory = 18,000 kg
90,000 = 18,000 + purchase - 18,000
So, the purchase is 90,000 kg
The question has asked the amount in kg so cost per kg is irrelevant.
Hence, the budgeted materials need in kg. in the first quarter is 90,000 kg
X = 10.71 rounded to the hundredth
Answer:
Full question: <em>On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes. Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?</em>
<em>Answe</em><em>r: Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
Explanation:
<em>From the given question let us recall the following statements:</em>
<em>Employees at a large company are permitted to take a 60-minute Lunch break instead of the 30 minutes.</em>
<em>Data was gotten from = 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday</em>
<em>Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.</em>
<em>The company tries to investigate the data to know that the mean is greater than 60 minutes</em>
<em>the next step is to find the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance</em>
<em>Therefore,</em>
<em>Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
<em>Or</em>
<em>The P-value> 0.05</em>
<em>The mean time is not greater than 60 minutes</em>
Answer:
option (b) 100K
Explanation:
Data provided in the question:
Total number of share holders = 3
Taxable income and current earnings and profits = 300K
Distributions made during 2009 = 120K
Now,
Since the shareholders are equal shareholders in Bow Inc,
Therefore,
The amount from Bow that should be included in each S/H's gross income will be
= ( Taxable income and current earnings and profits ) ÷ (Number of share holders)
= 300K ÷ 3
= 100K
Hence,
the answer is option (b) 100K
Answer:
Charge for perpetual care service will be $1500
So option (a) will be the correct option
Explanation:
We have given the estimated cost to maintain a gravesites is $120 per year
Interest rate = 8 % = 0.08
We have to find the fee which owner charged for the perpetual care service
The perpetual charge is given by
Charge for perpetual care service will be $1500
So option (a) will be the correct option
