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Paul [167]
2 years ago
8

Describe and correct the error in naming opposite rays in the diagram

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
5 0

The true statement about the opposite rays is YC and YE are opposite rays.

<h3>How to describe and correct the error in naming opposite rays in the diagram?</h3>

The complete options are added as an attachment

Two rays are opposite rays, if:

  • Their names begin with the same name
  • If their arrows point to opposite directions

Using the above highlights as a guide, we have:

  • YC and YE are opposite rays
  • XB and XD are opposite rays

Hence, the true statement about the opposite rays is YC and YE are opposite rays.

Read more about rays at

brainly.com/question/14366932

#SPJ1

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60 + 6 equals 13 + 5 p​
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Brainiest to whoever right
Anna35 [415]

Answer:

since M lies between point A and B , we came to know that,

M(4,6) =(x,y)

A(-2,-1)=(x1 ,y1)

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Now using mid point formula,

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6 0
3 years ago
Type the correct answer in each box. (____)
trapecia [35]

Answer:

1. -16; 2. +64; 3. 16

Step-by-step explanation:

The formula for the volume of a cylinder is

V = πr²x

Data:

r = (x - 8)   mm

V = 1024π mm³

Calculations:

1. Find the cubic equation  

V = πr²h

1024π = π(x - 8)² × x

Divide each side by π

1024 = x(x - 8)²  

1024 = x(x² - 16x  + 64)

1024 =    x³ - 16x² + 64x

x³ - 16x² + 64x - 1024 = 0

2. Solve the cubic equation

The general formula for a third-degree polynomial is

f(x) = ax³ + bx² + cx + d

Your polynomial is  

f(x) = x³ - 16x² + 64x - 1024

a = 1; d = -1024

According to the <em>rational roots theorem</em>, the possible roots are

factors of d/factors of a

Factors of d = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

Factors of a = ±1

Potential roots are x = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

That's a lot of possibilities to check by trial and error. I will just use the one that works.

Try x = 16 by synthetic division.

16|1  -16   64  -1024

  <u>|     16     0   1024 </u>

   1     0   64        0

So,

(x³ - 16x² + 64x - 1024)/(x – 16) = x² + 64

and

(x - 16)(x² + 64) = 0

x - 16 = 0        x² + 64 =    0

     x = 16       x²         = -64

                       x          =  ±8i

There is only one real root: x = 16 mm

6 0
4 years ago
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