Question

The force of repulsion, F Newton (N).,between particles is invesrly propotional to the square of the distance dm1find the particles with the force of repulsion 20N.Find find force when distance is halved

Answer 1

Answer:

$F_{2} = 80\,N$

Step-by-step explanation:

Given the consideration of the inverse proportionality between force and distance, the following relationship is constructed and described below:

$F_{1}\cdot r_{1}^{2} = F_{2}\cdot r_{2}^{2}$

The force when the distance is halved is:

$F_{2} = F_{1}\cdot \left(\frac{r}{0.5\cdot r} \right)^{2}$

$F_{2} = 4\cdot F_{1}$

$F_{2} = 4\cdot (20\,N)$

$F_{2} = 80\,N$