Answer:
[0.9 months, 32.69 months]
Step-by-step explanation:
The mean is
The standard deviation is
Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95
</em>
Using a spreadsheet we find these values are
a = 0.906
b = 32.694
<h3>(See picture)
</h3>
and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is
[0.9 months, 32.69 months]
Well, should be likee thiss correct meh if im wrong or what ever, but
the answer would be, last one (x + 8)(x - 8), well 1, is because the 64 is a negative so if you would just take that 64 and bring it down then look at this onece the work is donee then when u add the 2 numbers that x would be x² or x2 n that - 64 is that + 8 (-8) witch would equal out so if you really look at it the CORRECT ANSWER WOULD BE B. (x - 8)(x -8)
i realli understand if youu don't then comment in the sec beloww↓
The answer is c because the variable behind the number s are equal
Answer:
ok lol
Step-by-step explanation:
Answer:
- value: $66,184.15
- interest: $6,184.15
Step-by-step explanation:
The future value can be computed using the formula for an annuity due. It can also be found using any of a variety of calculators, apps, or spreadsheets.
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<h3>formula</h3>
The formula for the value of an annuity due with payment P, interest rate r, compounded n times per year for t years is ...
FV = P(1 +r/n)((1 +r/n)^(nt) -1)/(r/n)
FV = 5000(1 +0.06/4)((1 +0.06/4)^(4·3) -1)/(0.06/4) ≈ 66,184.148
FV ≈ 66,184.15
<h3>calculator</h3>
The attached calculator screenshot shows the same result. The calculator needs to have the begin/end flag set to "begin" for the annuity due calculation.
__
<h3>a) </h3>
The future value of the annuity due is $66,184.15.
<h3>b)</h3>
The total interest earned is the difference between the total of deposits and the future value:
$66,184.15 -(12)(5000) = 6,184.15
A total of $6,184.15 in interest was earned by the annuity.
