Answer:
2(20+5)
2(10+15)
Step-by-step explanation:
When you add 20+5 together you get 25 which is the same to 2(25)
When you add 10+15 together you get 25 which is the same to 2(25)
Answer:
2/3 = 0.666666667
<em><u>hopefully i helped :)</u></em>
<em><u></u></em>
Answer:
Brittany needs another $3.7405.
Step-by-step explanation:
Per pound Cost of turkey = $5.96 per pound
The amount Brittany buys the turkey = 2.55 pounds
Brittany's cost for turkey = 2.55 × $5.96 = $15.198
Per pound cost for cheese = $3.35 per pound
The amount Brittany buys the cheese = 3.7 pounds
Brittany's cost for cheese = 2.55 × $3.35 = $8.5425
So,
Brittany's total cost = Turkey cost + Cheese cost
= $15.198 + $8.5425
= $23.7405
As brittany gave the clerk 20 dollars.
So, the amount she further needs will be:
$23.7405 - $20 = $3.7405
Therefore, Brittany needs another $3.7405.
Answer:
t = 460.52 min
Step-by-step explanation:
Here is the complete question
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.
Solution
Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.
inflow = 0 (since the incoming water contains no dye)
outflow = concentration × rate of water inflow
Concentration = Quantity/volume = Q/200
outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.
So, Q' = inflow - outflow = 0 - Q/100
Q' = -Q/100 This is our differential equation. We solve it as follows
Q'/Q = -1/100
∫Q'/Q = ∫-1/100
㏑Q = -t/100 + c

when t = 0, Q = 200 L × 1 g/L = 200 g

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

㏑0.01 = -t/100
t = -100㏑0.01
t = 460.52 min