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BabaBlast [244]
2 years ago
8

Hey, I need to find the vertex and show work. The equation is down below and photo:

Mathematics
2 answers:
Vinvika [58]2 years ago
7 0

Answer:

y = x^2 + 4x - 7

y=833

Step-by-step explanation:

brainliest?

Dmitrij [34]2 years ago
6 0

Answer:

this answer for this question

y=833

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6 times the sum of y and 11
Gelneren [198K]

Answer:

6y+66

Step-by-step explanation:

write the problem out, placing 6 on its own, and the sum of y and 11 inside a pair of parentheses after the 6.

6(y+11)

then, just use the distributive property and multiply each term inside the coefficients by six. you'll get 6y+66 as your final answer.

if your teacher says that the final answer is not supposed to have variables in it, then we'll need a bit more information.

4 0
3 years ago
Help please if u<br> You don’t know it please don’t answer.
Bogdan [553]
I believe the answers are the following:

5. x = ±3.4641i

6. x = ±7

hope this helped! please mark brainliest if you get the chance :)
5 0
2 years ago
What is a reciprocals
kompoz [17]
Reciprocal: what to multiply a value by to get 1; also known as multiplicative inverse.
8 0
3 years ago
. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass
Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0
3 years ago
PLEASE HELP ASAP (8th grade question)
Ahat [919]

Answer:

m∠2=35°, m∠1=35°

Step-by-step explanation:

∠2 and ∠4 equal 180° when added, so 180-145=35

all angles of a triangle equal 180°, so 180-∠3-∠2=∠1

180-110-35= 35

6 0
3 years ago
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