Answer:
c =2
Step-by-step explanation:
2(6c+2)+3c=2 (19 -c)
1. Distribute
2(6c +2 ) + 3c = 2 ( 19 - C )
12c + 4 +3c = 2 (19 - C )
2. Combine like terms
12c + 4 + 3c = 2 ( 19 - c )
15c + 4 = 2 (19 - c )
3. Rearrange terms
15c + 4 = 2( 19 - C )
15c + 4 = 2 ( -c + 19 )
4. Distribute
15c + 4 = 2 ( -c + 19 )
15c + 4 = -2c + 38
5. Subtract 4 from both sides of the equation
15c + 4 = -2c + 38
15c + 4 -4 = -2c + 38 -4
6. Simplify
Subtract the numbers
Subtract the numbers
15c = -2c +34
7. Add 2c to both sides of the equation
15c = -2 +32
15c +2c = -2c + 34 + 2c
8. Simplify
Combine like terms
Combine like terms
17c = 34
9.Divide both sides of the equation by the same term
17c = 34
17c/17 = 34/17
10. Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
c = 2
Transpose the y into the left part of the equation and the 20 should be on the right
y= -20x
The answer to the problem is A
When you add integers, you keep the sign on the sum.
For example:
-9 + -9 = -18 (kept the sign)
9 + 9 = 18 (kept the "sign")
