Question

Use the Quadratic Formula to solve the equation. -2x^2 - 5x + 5 = 0

Answer 1

Answer:

$x = \frac{5 \pm \sqrt{ 65 }}{-4}$.

Step-by-step explanation:

The Quadratic Formula for a second degree polynomial $ax^{2} +bx+c=0$ is a formula for the values of its solution i.e. for finding the values of x.

It is given by, $x = \frac{-b \pm\sqrt{b^{2}-4ac }}{2a}$.

Now, we have the given quadratic equation $-2x^{2}-5x+5 = 0$,

which gives a = -2 , b = -5 , c = 5.

Substituting the value of a, b , c in the above formula, we get

$x = \frac{-(-5) \pm \sqrt{(-5)^{2} -4 \times (-2) \times 5 }}{2 \times (-2)}$.

$x = \frac{-(-5) \pm \sqrt{ 25 + 40 }}{-4}$.

$x = \frac{5 \pm \sqrt{ 65 }}{-4}$.

Hence, the solution of the given quadratic equation is $x = \frac{5 \pm \sqrt{ 65 }}{-4}$.

Answer 2

The answer is going to be in the picture because trying to make fractions with this is too difficult. :D