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77julia77 [94]
3 years ago
13

Find the percent.3 is what percent of 8?​

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

37.5

Step-by-step explanation:

3/8

3 divided by 8= .0375

.0375 times 100= 37.5

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While walking past a flag pole, Tommy looked down and noticed his shadow. Use the diagram below to
SashulF [63]

Answer: x=5.6

Step-by-step explanation:

3 0
2 years ago
Help cause everyone last time when i posted this question DIDNT help
Lorico [155]

Answer:

James is incorrect. A fraction can be interpreted as division of the numerator by the denominator.

Step-by-step explanation:

hope this helps :)

7 0
3 years ago
Ricky Major
Assoli18 [71]

Answer:

Step-by-step explanation:

The diameter of each curved path is 200 feet. Since the two curved semi circular paths are equal, they would form a circle. It means that the distance around the two semi circular paths would be the circumference of the circle. Formula for determining the circumference of the circle is π × diameter. It becomes

200 × 3.14 = 628 feet

Total distance around the track would be

300 + 300 + 628 = 1228 feet

5280 feet = 1 mile

1228 feet = 1228/5280 = 0.23 mile

If he runs around the track exactly 15 times, it means that the number of miles covered is

0.23 × 15 = 3.45 miles

Since he will collect $4.50 for every mile he runs, the amount of money that he collected is

4.5 × 3.45 = $15.5

5 0
3 years ago
Plz write this on paper help me and send it❤️
vovangra [49]

Answer:

1. 27^{\frac{2}{3} } =9

2. \sqrt{36^{3} } =216

3. (-243)^{\frac{3}{5} } =-27

4. 40^{\frac{2}{3}}=4\sqrt[3]{25} =4325

5. Step 4: (\frac{343}{27}) ^{-1} =\frac{27}{343}

6. D. -72cd^{7}

Step-by-step explanation:

Use the following properties:

a^{\frac{x}{y} } =\sqrt[x]{a^{y} }

\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

a^{-n} =\frac{1}{a^{n} }

(xy)^{z} =x^{z} y^{z} \\\\

(x^{y}) ^{z} =x^{yz}

x^{y} x^{z} =x^{y+z}

So:

1. 27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9

2. \sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36}  \sqrt{36} =6*6*6=216

3. (-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27

4. 40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325

5. (\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}

6.

(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}

7 0
3 years ago
What are zeros of function y=2x2 -3x-20, and why
kykrilka [37]
4 and -2.5

You can get this by first factoring the equation. 

(2x + 5)(x - 4)

Then set both equal to zero and solve individually. 
4 0
3 years ago
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