Volume of cube is width times length times height
So it's simply 1 unit × 1 unit × 1 unit = 1 unit³
Final answer: 1 unit³ (or 1 cubed unit)
Im not 100% sure what youre asking but if the value for C isnt given then it would be -7c because 3-10 is -7
(if theres a value for C can you let me know I can solve the actual thing it it would help more just lmk :)
The equations for the horizontal and vertical lines passing through the point (6,9) is y = 9 and x = 6 respectively
<u>Solution:</u>
Given, point is (6, 9)
We have to find the equations for horizontal and vertical lines passing through above given point.
Now, let us find horizontal line,
We know that, horizontal line is parallel to x – axis, so slope of our required line is 0.
The point slope form is given as
Then, line equation in point slope form ⇒ y – 9 = 0(x – 6)
⇒ y – 9 = 0
⇒ y = 9
Now, let us find vertical line,
We know that, vertical line is parallel to y – axis, so slope of our required line is undefined
Then, line equation in point slope form ⇒
⇒ x – 6 = 0(y – 9)
⇒ x – 6 = 0
⇒ x = 6
Hence, the horizontal line equation is y = 9 and vertical line equation is x = 6.
Answer:
the vertex angle = 80°
Step-by-step explanation:
V: vertex angle B: base angle
V / B = 8 / 5
5V = 8B
V + 2B = 180
4V + 8B = 720
4V + 5V = 720
9V = 720
V = 80°
check: B = (180 - 80) / 2 = 50°
V / B = 80 / 50 = 8 /5 (8 : 5)
Answer:
x = 8
m∠BOC = 37°
m∠AOB = 53°
Step-by-step explanation:
If OA is perpendicular to OC, this means that <AOC = 90°
Given
m∠BOC=6x−6
m ∠AOB = 5 x + 8
The expression is true
m∠BOC+m∠AOB= m∠AOC
6x-6+5x+8 = 90
Find x:
11x + 2 = 90
11x = 90-2
11x = 88
x = 88/11
x =8
Get m∠BOC:
m∠BOC= 6x-6
m∠BOC= 6(8)-11
m∠BOC = 48-11
m∠BOC= 37°
Get m∠AOB;
m∠AOB = 90-m∠BOC
m∠AOB =90-37
m∠AOB = 53°