The volume of the removed portion is 35 cm³.
Step-by-step explanation:
Given,
The length× width× height (L×B×H) of the outer part = 3 cm×3 cm×7 cm
The length× width× height (l×b×h) of the inner part = 2 cm×2 cm×7 cm
To find the volume of the removed portion.
Formula
The volume of the removed portion = volume of outer part - volume of inner part
Volume of rectangular prism = l×b×h
Now,
Volume of outer part = 3×3×7 cm³ = 63 cm³
Volume of inner part = 2×2×7 cm³ = 28 cm³
Hence,
The volume of the removed portion = 63-28 cm³ = 35 cm³
Answer:
<em>" Expected Payoff " ⇒ $ 1.56 ; Type in 1.56</em>
Step-by-step explanation:
Consider the steps below;
<em>Solution; " Expected Payoff " ⇒ $ 1.56</em>
Answer:
15x^2 - 12x^3
Step-by-step explanation:
A rectangular block has 3 parts that play into its volume. length, width and height. The question gives us length and width in the form of x and 3x, so height is what's missing.
It gives us a bit more information saying the sum of its edges is 20. We also have to ask how many lengths, widths and heights are there. That may be a bit hard to understand, but is you are looking at a block I could ask how many edges are vertical, just going up and down. These would be the heights. There are 4 total, and this goes the same for length and width, so 4*length + 4*width and 4*height = 20.
Taking that and plugging in x for length and 3x for width (or you could do it the other way around, it doesn't matter, you get:
4*x + 4*3x + 4*height = 20
4x + 12x + 4h = 20
16x + 4h = 20
4h = 20 - 16x
h = 5 - 4x
Now we have h in terms of x, which lets us easily find the volume just knowing x. To find the volume of a rectangular block you just multiply the length, width and height.
x*3x*(5-4x)
3x^2(5-4x)
15x^2 - 12x^3
Question doesn't give a specific value for x at all so you should be done there. Any number you plug in for x should get you the right answer
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
6/25 is the answer as a simplified fraction
