what is the critical f-value when the sample size for the numerator is six and the sample size for the denominator is four? use
1 answer:
The critical f-value when the sample size for the numerator and the denominator is given using a two-tailed test will be 0.12 and 14.88.
We have,
The sample size for the numerator = 6,
i.e.
Numerator degree of freedom = 6 - 1 = 5,
And,
The sample size for the denominator = 4,
i.e.
Denominator degree of freedom = 4 - 1 = 3
And,
We have to use a two-tailed test,
So,
The significance level = = 0.05
And,
Now,
The test follows the F-distribution with (5, 3) degrees of freedom,
Now,
Using the F-table at significance level 0.05 and check for given degrees of freedom,
We get,
Critical f-values : 0.12 and 14.88
Hence, we can say that the critical f-value when the sample size for the numerator and the denominator is given using a two-tailed test will be 0.12 and 14.88.
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Solving quadratic equations, it is found that he needs to charge:
1. He needs to charge $40 to break even.
2. He needs to charge $30 for a profit of $600.
<h3>What is a quadratic function?</h3>A quadratic function is given according to the following rule:
The solutions are:
In which:
The profit equation in this problem is:
P(x) = -3x² + 150x - 1200.
He breaks even when P(x) = 0, hence:
-3x² + 150x - 1200 = 0.
The coefficients are a = -3, b = 150, c = -1200, hence:
He needs to charge $40 to break even.
For a profit of $600, we have that P(x) = 600, hence:
-3x² + 150x - 1200 = 600.
-3x² + 150x - 1800 = 0.
The coefficients are a = -3, b = 150, c = -1800, hence:
He needs to charge $30 for a profit of $600.
More can be learned about quadratic equations at brainly.com/question/24737967
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