Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
0.5x22=11. To get answers like that, all you have to do is divide 11 by anything and then that number times the number you divided 11 by will give you the answer. So like 11 divided by 4 is 2.75. So 4x2.75=11.
The division ➗ ÷ sign will make the expression correct if you correct the question!
Answer:
8
Step-by-step explanation:
1 2 3 4 5 6 7 8 quick math
Answer:
6
Step-by-step explanation:
let the number be x
(x-2)3=x+6
3x-6 = x+ 6
2x= 12
x= 6
