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borishaifa [10]
3 years ago
9

A triangular building is bounded by three streets. The building measures approximately 83 feet on the first​ street, 189 feet on

the second​ street, and 178 feet on the third street. Approximate the ground area K covered by the building.
Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0
For this case we use Heron's formula to calculate the area of the building.
 We have then:
 A = root ((s) * (s-a) * (s-b) * (s-c))
 Where,
 s = (a + b + c) / 2
 Substituting values:
 s = (83 + 189 + 178) / 2
 s = 225 feet
 A = root ((225) * (225-83) * (225-189) * (225-178))
 A = 7352.509776 feet ^ 2
 Rounding off we have:
 A = 7353 feet ^ 2
 Answer:
 
The ground area K covered by the building is:
 
K = 7353 feet ^ 2
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sertanlavr [38]

\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
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\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}

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I hope this helps

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2 years ago
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The equation would be:

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