How many real and imaginary solutions does the equation x2−3x=−2x−7x^2-3x=-2x-7x2−3x=−2x−7 have?
1 answer:
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to find the equation of a line i need two points
let
point A-----> (-21,10)
point B-----> (-28,14)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7
step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2
step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5
the x intercept is (-3.5,0)
step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)
the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)
see the attached figure
to find the equation of a line i need two points
let
point A-----> (-21,10)
point B-----> (-28,14)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7
step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2
step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5
the x intercept is (-3.5,0)
step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)
the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)
see the attached figure
Graham: -50x + 14,040
Max: 20x + 12,500
Graham = Max
-50x + 14,040 = 20x + 12,500
<u>+50x </u> <u>+50x </u>
14,040 = 70x + 12,500
<u> -12,500 </u> <u> -12.500 </u>
1,540 = 70x
220 = x
Answer: 220 minutes <em>(3 hours 40 minutes)</em>