THIS IS SOOOO URGENT! PLEASE!
2 answers:
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Answer:
hey hope this helps
<h3 /><h3>Comparing sides AB and DE </h3>AB =
DE
So DE = 2 × AB
and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.
<u>scale factor</u> = AB/DE
= 2
It's been reflected across the Y-axis
<em>moved thru the translation of 3 units towards the right of positive x- axis </em>
for this let's compare the location of points B and D
For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3
so the triangle has been shifted by 3 units across the positive x axis
Answer:
They are similar by the definition of similarity in terms of a dilation
Step-by-step explanation:
The given vertices of triangle ΔABC are;
A(1, 5), B(3, 9), and C(5, 3)
The vertices of triangle ΔDEF are;
D(-3, 3), E(-2, 5), and F(-1, 2)
Therefore, we get;
The length of segment, = √((9 - 5)² + (3 - 1)²) = 2·√5
The length of segment, = √((9 - 3)² + (3 - 5)²) = 2·√10
The length of segment, = √((5 - 3)² + (1 - 5)²) = 2·√5
The length of segment, = √((5 - 3)² + (-2 - (-3))²) = √5
The length of segment, = √((2 - 5)² + (-1 - (-2))²) = √10
The length of segment, = √((2 - 3)² + (-1 - (-3))²) = √5
∴ /
= 2·√5/(√5) = 2
/
= 2·√10/(√10) = 2
/
= 2·√5/(√5) = 2
The ratio of their corresponding sides are equal and therefore;
ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.