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Stella [2.4K]
3 years ago
9

What are the possible values of x in 8^2+4x = -1

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

So we can simplify this to

36+4x=-1

We can subtract by 64 on both sides. 4x = -37. Therefore the answer to this is

x = -37/4 = -9.25.

So the answer for x is -16.25. If you were trying to do a quadratic equation then sorry because you worded it wrong, and I solved properly.

<h2 /><h2><u>Answer: -9.25</u></h2>

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What expressions are equivalent to 7^3 * 7^x
solong [7]

Answer:

The question = (7^3)*(7^x)

When multiplying two exponents with the same base, all you do is add the exponents together and keep the same base

Therefore,

(7^3)*(7^x) = 7^(3+x)

Step-by-step explanation:

7^3+x is the answer

3 0
3 years ago
HELP I WILL MARK BRAINLIEST!!!
MrMuchimi

Answer:

17.7 as the actual gas mileage recorded is 12 mpg.

Step-by-step explanation:

8 0
3 years ago
Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p
Juli2301 [7.4K]
I'm reading this as

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy

with \nabla f=(2xe^{-y},2y-x^2e^{-y}).

The value of the integral will be independent of the path if we can find a function f(x,y) that satisfies the gradient equation above.

You have

\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}

Integrate \dfrac{\partial f}{\partial x} with respect to x. You get

\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx
f=x^2e^{-y}+g(y)

Differentiate with respect to y. You get

\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]
2y-x^2e^{-y}=-x^2e^{-y}+g'(y)
2y=g'(y)

Integrate both sides with respect to y to arrive at

\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy
y^2=g(y)+C
g(y)=y^2+C

So you have

f(x,y)=x^2e^{-y}+y^2+C

The gradient is continuous for all x,y, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e
8 0
3 years ago
Complete the table below.
Nana76 [90]
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Angle 2 is 87 degrees bc of alt ext angle converse
Angle 3 93 degrees
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7 0
2 years ago
CHECK YOUR KNOWLEDGE
PIT_PIT [208]
1. A rent paid
2. B 10
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