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Stella [2.4K]
3 years ago
9

What are the possible values of x in 8^2+4x = -1

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

So we can simplify this to

36+4x=-1

We can subtract by 64 on both sides. 4x = -37. Therefore the answer to this is

x = -37/4 = -9.25.

So the answer for x is -16.25. If you were trying to do a quadratic equation then sorry because you worded it wrong, and I solved properly.

<h2 /><h2><u>Answer: -9.25</u></h2>

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A 6-pack of batteries cost $10.50.what is the unit price
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Unit price = $1.75

Step-by-step explanation:

In order to determine the unit price of the batteries, divide the $10.50 total price for the 6-pack of batteries by 6:

$10.50 ÷ 6 = $1.75

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Alejandro bought $3.50 worth of pencils and erasers at the school store. Pencils cost $0.50 apiece, and erasers cost $0.75 apiec
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Answer:

I would say that is is B

Step-by-step explanation:

Just put the answer

Please make be brainliest or like rate my answer please and thanks <3

5 0
3 years ago
It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

8 0
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