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babunello [35]
3 years ago
7

Out of 8 boys and 6 girls in a high school, a team of seven students is selected. What is the probability that three boys and fo

ur girls are selected? In your response, include an explanation and all of the calculations necessary to determine the probability.
Mathematics
1 answer:
maria [59]3 years ago
7 0
The probabitily is if they get selected  as a team of 7 aswell if they're playing a game of some sort.
 
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The price of a stock had a change of –3 dollars. explain how you would use a number line to find the absolute value of –3.
Naya [18.7K]
Draw out a horizontal line. Place 0 at the center. Then place evenly spaced tick marks on either side of 0. Label the right side of tick marks as 1, 2, 3, ... moving from 0 and going to the right

Label the left side of tick marks -1, -2, -3, ... starting at 0 and moving left

The location -3 on the number line is exactly 3 units away from 0. We start at 0 and move to -3 by moving 3 spots to the left; or we start at -3 and move 3 units to the right to get to 0.

Therefore, the absolute value of -3 is 3
Absolute value on a number line is the distance a number is from 0
The distance is never negative
5 0
3 years ago
Read 2 more answers
Helllllppp please asap
BartSMP [9]

Answer:

1). a = 9.42 m

2). b = 6.37 m

3). c = 4.48 m

Step-by-step explanation:

In the figure attached,

By applying tangent rule in triangle ADE,

tan47 = \frac{h}{c}

c = \frac{h}{\text{tan}47}

c = \frac{4.8}{\text{tan}47}

c = 4.476

c ≈ 4.48 m

Now we apply the same rule in triangle ACE,

tan37° = \frac{h}{b}

b = \frac{h}{\text{tan}37}

b = \frac{4.8}{1.0724}

b = 6.37 m

Now apply the tangent in triangle ABE,

tan27° = \frac{h}{a}

a = \frac{h}{\text{tan}27}

a = \frac{4.8}{0.5095}

a = 9.42 m

5 0
3 years ago
Write as a product: ax^2+ay^2–bx^2–by^2+b–a
Vesna [10]

Answer:

\large\boxed{ax^2+ay^2-bx^2-by^2+b-a=(a-b)(x^2+y^2-1)}

Step-by-step explanation:

ax^2+ay^2-bx^2-by^2+b-a\\\\=(ax^2-bx^2)+(ay^2-by^2)+(b-a)\qquad\text{use the distributive property}\\\\=x^2(a-b)+y^2(a-b)-1(a-b)\\\\=(a-b)(x^2+y^2-1)

4 0
3 years ago
If f(x)=3x^2+2×=1 find f(x+2)​
harkovskaia [24]

Answer:

f(x+2) = 3(x+2)^2 + 2(x+2 + 1

Step-by-step explanation:

you need to replace the x with x+2

3 0
3 years ago
2. Solve: 33 + 2(5+8)-(6-2)
mars1129 [50]

Answer:

55

Step-by-step explanation:

Add the numbers 5 + 8 and you get 13. Multiply 13 x 2 which is 26. Add 33 + 26 and you get 59. Then, subtract it by 4 and you get 55.

6 0
3 years ago
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