The area of a rectangle is given by A = length * width.
width of the given rectangle is x
height is y = 2 - x^2
Area = x(2 - x^2) = 2x - x^3
For area to be maximum, dA/dx = 0
dA/dx = 2 - 3x^2 = 0
3x^2 = 2
x^2 = 2/3
x = √(2/3)
y = 2 - (√(2/3))² = 2 - 2/3 = 4/3
Therefore, the required rectangle has a width of 2√(2/3) ≈ 1.63 and a height of 4/3 ≈ 1.33
Answer:
Step-by-step explanation:
Lack of information
Answer:
Step-by-step explanation:
1 in = 2.54 cm
Part (a)
Answer: 8.268 in
Part (b)
Answer: 11.693 in
Part (c)
In SI units standard-sized paper is 21.0 cm by 29.7 cm, which is equivalent to 8.268 in by 11.693 in.
Answer: 8.268 in by 11.693 in.
Part (d)
The U.S sized standard paper is 8.0 in by 11.0 in. Therefore the SI (internationally) sized paper is longer.
Part (e)
If the U.S> adopts the SI standard for letter-sized paper, both the width and length of standard paper will have to be increased. Therefore letter-sized paper will occupy a larger area and will be heavier if the thickness and density do not change.
Yes, the new traffic lights have had an effect, as only 58.48% of surveyed cars had encountered a traffic jam, compared to 60% before the installation of the traffic lights.
Answer:
Tina is correct
Step-by-step explanation:
Given
Required
State if is a possible dimension
To do this, we simply expand
By comparison, the result of the expansion
and the given expression
are the same.
<em>Hence, Tina is correct</em>