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2 years ago

Name the geometric term(s) modeled by each object

Mathematics

1 answer:

anyanavicka [17]2 years ago

3 0

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The geometric term(s) modeled by each object are Hexagon, point, line, line, and plane, respectively.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. A line segment is also a line but the line with finite length and having fixed endpoints.

The geometric term(s) modeled by each object

9. Stop sign ⇒ Hexagon

10. Tip of pin ⇒ Point

11. Strings of a violin ⇒ Line

12. A car antenna ⇒ Line

13. A library card ⇒ Plane

Hence, The geometric term(s) modeled by each object are Hexagon, point, line, line, and plane, respectively.

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9.51 as a mixed number in a simplest form

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Answer:

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Step-by-step explanation:

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3 years ago

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A blueprint for a new house has a scale of 1:50. Here are the dimensions of two rooms. Calculate the dimensions of each room on

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Answer:

a.) =30.72*50

b.)13.02*50

Step-by-step explanation:

you got to calculate the area of the two rooms by multipling the sides.

as we know that the scale is 1:50, this means for every 1meter it is 50 meters.

once we have calculated the area of the space used multply it by 50 to get the area dimensions occupied

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3 years ago

Which graph represents y= ^3 square root of x +2?

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$y = \sqrt[2]{x}+2 \: will \: pass \: through \: (0 \:, 2) \: and \: ( - 8 \:, 0)$

Step-by-step explanation:

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2 years ago

A company wants to find out if the average response time to a request differs across its two servers. Say µ1 is the true mean/ex

lorasvet [3.4K]

Answer:

a) The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

Test statistic t=0.88

The P-value is obtained from a t-table, taking into acount the degrees of freedom (419) and the type of test (two-tailed).

b) A P-value close to 1 means that a sample result have a high probability to be obtained due to chance, given that the null hypothesis is true. It means that there is little evidence in favor of the alternative hypothesis.

c) The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

d) The consequences of the confidence interval containing 0 means that the hypothesis that there is no difference between the response time (d=0) is not a unprobable value for the true difference.

This relate to the previous conclusion as there is not enough evidence to support that there is significant difference between the response time, as the hypothesis that there is no difference is not an unusual value for the true difference.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that there is significant difference in the time response for the two servers.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

$M_d=M_1-M_2=12.5-12.2=0.3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{3^2}{196}+\dfrac{4^2}{225}}\\\\\\s_{M_d}=\sqrt{0.046+0.071}=\sqrt{0.117}=0.342$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.3-0}{0.342}=\dfrac{0.3}{0.342}=0.88$

The degrees of freedom for this test are:

$df=n_1+n_2-1=196+225-2=419$

This test is a two-tailed test, with 419 degrees of freedom and t=0.88, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>0.88)=0.381$

As the P-value (0.381) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is significant difference in the time response for the two servers.

<u>Confidence interval </u>

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

The estimated standard error of the difference is s_Md=0.342.

The critical t-value for a 95% confidence interval and 419 degrees of freedom is t=1.966.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=1.966 \cdot 0.342=0.672$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 0.3-0.672=-0.372\\\\UL=M_d+t \cdot s_{M_d} = 0.3+0.672=0.972$

The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

7 0

3 years ago

Sally invests £8000 in a savings account. The account pays 2.8% compound interest per year work out the value of her investment

Alborosie

Answer: the value of her investment after 4 years is £8934.3

Step-by-step explanation:

The formula for determining compound interest is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount invested.

t represents the duration of the investment in years.

From the information given,

P = 8000

r = 2.8% = 2.8/100 = 0.028

n = 1 because it was compounded once in a year.

t = 4 years

Therefore,

A = 8000(1+0.028/1)^1 × 4

A = 8000(1+0.028)^4

A = 8000(1.028)^4

A = £8934.3 to the the nearest penny

6 0

3 years ago