Answer:
26 in²
Step-by-step explanation:
Hope this helps :)
Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t -
) And
yB = 8 sin(2t -
)
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( -
+
)
Or, phase difference between yA and yB = 
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is
Answer
Answer:
We'd need more information like the relationship between those equations.
Step-by-step explanation:
Sa= bw+hw+lw+

(2)
SA=(12*4)+(16*4)+(20*4)+(

)
SA= 28+64+80+(6*16*2)
SA=28+64+80+(96*2)
SA=28+64+80+192
SA=364
Answer:
34
Step-by-step explanation:
i honestly don't care i came on here to cheat but it's saying answer so here you go :)