-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are blue-green-black.
Now the rest of the collection consists of
4 blue
4 green
2 black
and there's space for 2 more marbles in the case.
So the question really asks: "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"
-- Well, there are 10 marbles all together.
So the first one chosen can be any one of the 10,
and for each of those,
the second one can be any one of the remaining 9 .
Total number of ways to pick 2 out of the 10 = (10 x 9) = 90 ways.
-- BUT ... there are not nearly that many different combinations
to wind up with in the case.
The first of the two picks can be any one of the 3 colors,
and for each of those,
the second pick can also be any one of the 3 colors.
So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
Answer:
m∠1=77°
m∠2=36°
m∠3=30°
Step-by-step explanation:
First, find angle 1 by adding 66 and 37 and subtracting them from 180 because there are 180 degrees in an angle.
180-(66+37)=77°
You can then find angle 2 by finding the other angle not given. You can find this angle by subtracting 77 from 180, giving you 103. To find angle 2, add 103 and 41 and subtract them from 180.
180-(103+41)=36°
You can then find angle 3 by adding the angle 103 and the angle 47, and subtracting them from 180
180-(103+47)=30°
Answer:
tgtutyffyfyfyfyfydryd7dudududyfyf7
Answer:37 degrees
The processed I used to solve is below. If you have an questions let me know!
Answer:
Besty Ross
Step-by-step explanation:
Brainllest
