1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katarina [22]
3 years ago
5

Simplify completely 12x^3-4x^2+8x/-2x PLEASE HELP

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0
The answer is 12x^3-4×^2-4
You might be interested in
Calculate s26 for the arithmetic sequence in which a14=4.1 and the common difference is d=1.7
sweet-ann [11.9K]

Answer:

The value of s_{26}=84.5

Step-by-step explanation:

We have given  a_{14}=4.1

d=1.7

We have to find s_{26}

So, a_{14}=a+13d from the formula

a_n=a+(n-1)d

When n=14

a_{14}=a+(14-1)(1.7)=a+13(1.7)

4.1=a+22.1

-18=a

a=-18

Using the formula:

s_n=\frac{n}{2}[2a+(n-1)d

When n=26

s_{26}=\frac{26}{2}[2(-18)+(26-1)(1.7)]

On simplification we get:

s_{26}=84.5



8 0
3 years ago
Prime number between 60 and 80 with the 10’s digit being one less than the 1st digit
erastova [34]

It would be 89.

You can also just look up a list of prime numbers online.

8 0
4 years ago
Rafael Drive 405 miles using 20 gallons of gas. At that rate, how many gallons of gas would he need to drive 243 miles?
ANEK [815]
This is how I'd set it up:
405/20 = 243/x 
this means the mpg (miles / gallons) for 1 situation is the same as the mpg for the other situation (because the rate is the same)
then just cross multiply and solve:
405x=243*20 or 405x=4860 or x = 12
he would need 12 gallons of gas for 243 miles
3 0
4 years ago
The Yoga class you wish to take is offering two price quotes: $120 for 5 weeks as (15 classes) or $160 for 8 weeks (24 classes).
True [87]

The answer is B $1.05




3 0
3 years ago
7.
Serjik [45]

Answer:

Probability that a customer pays the bill by mail, given that the customer is female is 0.20.

Step-by-step explanation:

The complete question is:

                               Online                             By Mail            Total

             Male             12                                      8                   20

           Female           24                                     6                   30      

             Total             36                                     14                  50    

A utility company asked 50 of its customers whether they pay their bills online or by mail. What is the probability that a customer pays the bill by mail, given that the customer is female.

Probability that a customer pays the bill by mail, given that the customer is female is given by = P(Pays bill by mail / Customer is female)

\frac{6}{50}P(Pays bill by mail/Customer is female) = \frac{P(\text{Pays bill by Mail}\bigcap \text{ Customer is Female})}{P(\text{ Customer is Female})}

Now, Probability that customer is female =  \frac{30}{50}

Also, Probability that customer pays bill by mail and is female =   \frac{6}{50}

So, Required probability =  \frac{\frac{6}{50} }{\frac{30}{50} }

                                         =  \frac{6}{50}\times \frac{50}{30}

                                         =  \frac{1}{5}   =  0.20

Hence, probability that a customer pays the bill by mail, given that the customer is female is 0.20.

6 0
3 years ago
Other questions:
  • Estimate the product of 25.311 × 4.65.
    13·1 answer
  • Please help!!will get brainliest!!
    12·1 answer
  • Joe's bank account decreases by $1.50
    5·2 answers
  • Define the word factor mathmatically
    6·2 answers
  • Help please! Quick math question
    15·1 answer
  • To make hummingbird
    15·1 answer
  • Gabriela makes a profit of $0.80 for every cup of coffee that she sells at her coffee shop. She wanted to make a profit of at le
    15·2 answers
  • I need to find the area
    8·2 answers
  • Reposting because I really need this fast​
    14·1 answer
  • What is the surface area of the right cone below?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!