Answer: compare the relative strength of coefficients.
Step-by-step explanation: The Coefficient of determination usually denoted as R^2 is obtained by taking the squared value of the correlation Coefficient (R). It's value ranges from 0 to 1 and the value obtained gives the proportion of variation in the dependent variable which could be attributed to it's correlation or relationship to th independent variable. With a R^2 value close to 1, this means a large portion of Variation in a variable A could be explained due to changes in variable B while a low value signifies a low variance between the variables. Hence, the Coefficient of determination is used in comparing the relative strength of the Coefficients in other to establish whether a weak or strong relationship exist.
Answer:
Step-by-step explanation:
Note that the entire segment RT is the combined lengths of RS and ST. So:
We know that RT is 108, RS is (9y+5), and ST is (3y+7). Substitute:
On the right, combine like terms:
Add:
Subtract 12 from both sides. The right cancels:
Divide both sides by 12:
So, the value of y is 8.
To find RS and ST, substitute 8 for y. So:
Substitute 8 for y:
Multiply:
Add:
Do the same for ST:
Substitute 8 for y:
Multiply:
Add:
Answer: 
This means that he has to save at least $88 or more to have enough money.
Step-by-step explanation:
He has $37 and he needs to save more (+) but we don't know how much more that is, so that's why that is our unknown value. (x). The sum of them has to be at least 125 or greater.
Subtract 37
The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars
<h3>Arithmetic sequence</h3>
- First month, a = 4,600 cars
- Common difference, d = -50 cars
First five terms;
a = 4,600
a + d = 4600 + (-50)
= 4600 - 50
= 4,550
a + 2d
= 4600 + 2(-50)
= 4600 - 100
= 4,500
a + 3d
= 4,600 + 3(-50)
= 4,600 - 150
= 4,450
a + 4d
= 4600 + 4(-50)
= 4,600 - 200
= 4,400
cars predicted for the twelfth month.
a + 11d
= 4600 + 11(-50)
= 4600 + 550
= 4,050
Total predicted number of sold cars for the first year:
Sn = n/2{2a + (n - 1)d }
= 12/2{2×4600 + (12-1)-50}
= 6{9200 + 11(-50)}
= 6(9,200 - 550)
= 6(8,650)
= 51,900 cars
Learn more about arithmetic sequence:
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Show a picture of it I can’t see one
