How many students did he surveyplssss hurry I'll give BRAINLY pls
1 answer:
You might be interested in
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
see explanation
Step-by-step explanation:
using the identity
cos2a = 2cos²a - 1 , then
cos2a
= 2[ (a +
) ]² - 1
= 2 [ (a² +
+ 2) ] - 1
= (a² +
) + 1 - 1
= (a² +
) ← thus verified