3.because I found it. hahaha
Answer:
-5
Step-by-step explanation:
Divide -10 by 2 and you'll come away with -5
Answer:
The slope of the line is 8.
Step-by-step explanation:
The points on the straight line are:
A = (-1, -12)
B = (9, 68)
Compute the slope of the line as follows:
![m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
![=\frac{68-(-12)}{9-(-1)}\\\\=\frac{68+12}{9+1}\\\\=\frac{80}{10}\\\\=8](https://tex.z-dn.net/?f=%3D%5Cfrac%7B68-%28-12%29%7D%7B9-%28-1%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B68%2B12%7D%7B9%2B1%7D%5C%5C%5C%5C%3D%5Cfrac%7B80%7D%7B10%7D%5C%5C%5C%5C%3D8)
Thus, the slope of the line is 8.
Answer:
(q,0)
Step-by-step explanation:
See the diagram given.
It is clear from the coordinates of the points given that point C (0,r) lies on the Y-axis and point E (-q,o) lies on the X-axis. Hence, point D must be on the X-axis.
ΔCDE being an isosceles triangle, the origin of the coordinate axes will be on the DE line and it will be at the midpoint of DE.
Therefore, ΔCDE will be symmetric with respect to the Y-axis and the coordinates of point D will be (q,0). (Answer)
Answer:
Step-by-step explanation:
Keep in mind that the tangent function is negative in Quadrants II and IV.
Of the three possible answers, the 2nd is invalid because the tangent is positive in Q III.
If the reference angle were in Quadrant II and had the value 30° (second possible answer), then the opposite side would be +1, the adjacent side -√3 and the hypotenuse 2. Based on this, the tangent of theta would be opp / adj, or +1 / (-√3) or -√3/3. This is correct.