It is not possible to have 2 even factors
Answer:
- 6 + 3
Step-by-step explanation:
hope this helps
Answer:
<h2>
-27/4</h2>
Step-by-step explanation:
Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.
Factorizing the resulting equation to get the roots
x²- 5x + 4 = 0
(x²- x)-(4 x + 4) = 0
x(x-1)-4(x-1) = 0
(x-1)(x-4) = 0
x-1 = 0 and x-4 = 0
x = 1 and x = 4
Since a and b are known to be the root then we can say a = 1 and b =4
Substituting the given values into the equation 1/a+1/b-2 ab
, we will have;
= 1/1 + 1/4 - 2*1*4
= 1 + 1/4 - 8
= 5/4 - 8
Find the Lowest common multiple
= (5-32)/4
= -27/4
<em>Hence the required value is -27/4</em>
Answer:
I think its 4 because all the other ones are adding half of the original number
16-24 adds 8
8-12 adds 4
1-1.5 adds .5
so if it's going to 6 it should be 4 adding 2
