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Marina CMI [18]
2 years ago
14

Is not a type of variable in a scientific experiment?

Physics
1 answer:
Anastasy [175]2 years ago
6 0

Observation is not a type of variable in a scientific experiment; option D

<h3>What are variables in a scientific experiment?</h3>

Variables are those factors which affect the results of an observation or test in a scientific experiment.

The changes that occur in variables are controlled by the experimenter in order to bring about changes in the observations or the result of the experiment.

The following are the types of variables in a scientific experiment:

  • Independent variable
  • Dependent variable
  • Constant variable

The dependent variable changes when the independent variable is altered. The constant variable is not altered in an experiment but is kept constant.

In conclusion, variables are factors whose changes bring about changes in the results of an experiment.

Learn more about variables at: brainly.com/question/2804470

#SPJ1

Note that the complete question is found below:

Which of the following is not a type of variable in a scientific experiment? A. Independent B. Control C. Dependent D. Observation

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Hello, please anybody help if you can!!
Vinil7 [7]
This is called "projectile motion".  The projectile can be a baseball,
a bullet, a golf ball, or a rock that somebody tossed.  In this story, 
the swimmer is the projectile.

In projectile motion, the projectile is moving part horizontally and part
vertically at the same time.  The thing to remember about this kind of
motion is:  The horizontal motion doesn't change, but the vertical motion
changes because of gravity ... just like an apple that fell from a tree.

The swimmer runs straight horizontally off the diving board.  His horizontal speed is 3.62 m/s.  He hits the water  1.68 m from the end of the board.  How long did it take him to go that far ?

       Time  =  (distance) / (speed)

                 =  (1.68 m) / (3.62 m/s)

                 =  (1.68 / 3.62)  seconds

                 =          0.464 second .

(a).
How high above the water was the diving board ?
Well, the swimmer was falling for 0.464 second .
The height is whatever it takes 0.464 second to fall.

           Height  = (1/2) x (acceleration of gravity) x (time)²

                        = (1/2) x      (9.8 m/s²)                  x (0.464 sec)²

                        =        (4.9 m/s²)                x             (0.2153 sec²)

                        =              (4.9  x  0.2153)     meters

                        =                    1.055  meters .  

(b). 
If the swimmer runs off the board slower, his horizontal speed is
lower.  That only affects how far out in front of the board he'll be
when he hits the water.  But his horizontal speed has no effect
on how long it takes him to fall to the water.  That's his vertical
speed, and it only depends on gravity. 
No matter how fast or slow he runs off the board, or if he just
stands there at the end and leans over until he falls, it takes him
the same time to reach the water in every case.
6 0
3 years ago
A cylinder of radius r=10.0 cm and height h=20.0 cm
Olenka [21]
D I think is the correct answer
If the cylinder is slightly
7 0
2 years ago
Starting with a constant velocity of 45 km/h, a car accelerates for 35 seconds at an acceleration of 0.45 m/s2 . What is the vel
DENIUS [597]

Answer:

28.3 m/s

Explanation:

Vi = 45 Km/h = 12.5 m/s

Vf - Vi = at

Vf -12.5 = 0.45(35)

Vf= 28.3 m/s

5 0
3 years ago
If a galaxy is located 200 million light years from Earth, what can you conclude about the light from that galaxy?
natulia [17]
If a galaxy is located 200 million light years from Earth, you can conclude that t<span>he light will take 200 million years to reach Earth. </span>
8 0
3 years ago
Read 2 more answers
The velocity of a particle (m = 10 mg, q = –4.0 μC) at t = 0 is 20 m/s in the positive x direction. If the particle moves in a u
kompoz [17]

Answer:

Vf = - 20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction).

Explanation:

Given:

Vi = 20 m/s, m= 10 mg =1 × 10⁻⁵ kg, q= -4.0 × 10⁻⁶ C , E= 20 N/C. t= 5.0 s

first to find Electric Force

F= Eq = 20 × -4.0 10⁻⁶ C = - 8 × 10⁻⁵ N (-ve sign shows that the field will push the particle opposite to positive x- direction)

We also have F=ma

⇒ a = F/m =  - 8 × 10⁻⁵ N / 10 × 10⁻⁵ kg = -8 m/s² ( -ve sign shows that the particle is accelerated opposite to positive x- direction)

Now according the first equation of Motion.

Vf = Vi + at

Vf = 20 m/s + -8 m/s² × 5 s

Vf= -20 m/s ( -ve sign shows that the particle is moving opposite to positive x- direction)

6 0
4 years ago
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