It’s b for sure since the waves move on the ocean
Answer:
.
Explanation:
By Newton's Second Law, the acceleration of an object is proportional to the net force on it. In particular, if the mass of the object is , then
.
Rewrite this equation to obtain:
.
In this case, the assumption is that the force is the only force that is acting on the object. Hence, the net force on the object would also be
Make sure that all values are in their standard units. Forces should be in Newtons (same as , and the acceleration of the object should be in meters-per-second-squared (). Apply the equation to find the mass of the object.
.
Hey there! :D
Force is energy or strength that as the characteristic of movement or physical action.
A push or pull is a force. It moves something physically. If I was going to push a door for it to open, I would physically be moving it.
Inertia is a common tendency to remain unchanged or do nothing. If you are not doing anything, you are not applying force or movement to anything. This would not be the correct answer. We can eliminate "C" and "E"
Since a push and pull both are a force, then "D" is the answer. They both are.
I hope this helps!
~kaikers
Answer:
Kinetic energy of diver at 90% of the distance to the water is 9000 J
Explanation:
Let d is the distance between the position of the diver and surface of the pool.
Initially, the diver is at rest and only have potential energy which is equal to 10000 J.
As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.
Energy before diving = Energy during diving
(Potential Energy + Kinetic Energy) = (Kinetic Energy + Potential Energy)
When the diver reaches 90% of the distance to the water, its kinetic energy
is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,
K.E. =
K.E. = 9000 J
Answer:
1.97 × 10⁻¹⁸J
Explanation:
Charge of an electron q = -1.9 × 10⁻¹⁹C
Length of one side of the equilateral triangle at whose corners electrons are placed d = 3.5 × 10⁻¹⁰m
Coulomb constant k = 8.99 × 10⁹Nm²/C²
electrostatic potential = (3 kq²) / d
= (3 × 8.99 × 10⁹ × (-1.6 × 10⁻¹⁹)²) / 3.5 × 10⁻¹⁰
= 1.97 × 10¹⁸J