Answers may vary here are all the possible answers:
(R) = red
(G)= green
12 (R) 1 (G)
11 (R) 2 (G)
10 (R) 3 (G)
9 (R) 4 (G)
8 (R) 5 (G)
7 (R) 6 (G)
Your answer will be -2+2+4= 4
-3-1+4=0
so it will be 4,0
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
Answer:
It is 11/15
Step-by-step explanation:
First u add all the numbers to get the total which is 15. Then u add the number of beads that are not pink so it is 7+4 which is 11/15
Elimination:
3x - 9y = 3
6x - 3y = -24
3x - 9y = 3
18x - 9y = -72
(subtract)
-15x = 75
÷ -15
x = -5
(3 × -5) - 9y = 3
-15 - 9y = 3
+ 15
-9y = 18
÷ -9
y = -2
Substitution:
6x - 3y = -24
+ 3y
6x = -24 + 3y
÷ 6
x = 4 + 0.5y
3(4 + 0.5y) - 9y = 3
12 + 1.5y - 9y = 3
12 - 7.5y = 3
- 12
-7.5y = -9
÷ -7.5
y = 1.2
x = 4 + (0.5 × 1.2)
x = 4 + 0.6
x = 4.6
So this one didn't fail as much, but I got different numbers. If you have to give in values, I'd give in the values from the elimination because I don't trust myself when it comes to the substitution
