<h2>
Explanation:</h2>
Hello, remember you need to write complete questions in order to get good and exact answers. Here you haven't provided any fractions, so I'll give you my own fractions.
The first fraction is:
The second fraction is:
So let's say that difference is:
Therefore, the result is:
The representation of this problem is shown using the number line below. As you can see, we have written both 1/2 and 1/4 and the difference is also indicated giving the result 1/4. That is, if we walk from 1/4 to 1/2 we'll walk 1/4 units.
Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>
Considering the data given:
<h3>What is the mean and the standard error for the distribution of differences?</h3>
The mean is the subtraction of the means, hence:
The standard error is the square root of the sum of the variances of each sample, hence:
<h3>What is the confidence interval?</h3>
It is given by:
We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
Answer:
$190 is the answer
minus $5 from $97.50 and add that number to $97.50
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Answer: 3/11 & 6/10
Step-by-Step explanation:
there are 11 crayons, 3 of which are red so the chance of picking a red one is 3 out of 11. now that you have taken out a crayon you take the original number and take away 1
11 - 1 = 10
so the chance of taking a blue canyon out is 6/10.
these events are dependent because if you didn't take the first crayon out of the supply box the answer would be 6/11 instead of the 6/10 we have
