Answer:
a) 
, b) 
, 
, c) , d)
Step-by-step explanation:
a) Let derive the function:
is undefined when denominator equates to zero. The critical point is:
b) 
when numerator equates to zero. That is:
This equation shows two critical points:
,
c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that corresponds to a local maximum. (See Attachment)
d) By plotting the function, it is evident that corresponds to a local minimum. (See Attachment)
Answer: f(x)=(x+2)(4x-3)(x-5)
Step-by-step explanation:
Alg2.2.5 practice 2
It is -p... think about it.... two negative signs equal a positive sign, if there are an odd number of negative sign's the real answer is -p, and if there is an even amount, it means it is positive p. In your situation, there are 5 negative signs, so since 5 is an odd number, the p has to be negative.
The function is decreasing from -6 to -3, that is, on the interval (-6,-3), and again on the interval (1, infinity).
The function is increasing on (-3,1).
No local or absolute minimum.
(1,4) is an absolute max.
the answer 11
Step-by-step explanation:
6+16=22
22÷2=11
