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Naya [18.7K]
2 years ago
14

How many total moles of ions are released when each of the following dissolves in water?

Chemistry
1 answer:
bonufazy [111]2 years ago
7 0

2.202 moles of ions are released when samples dissolves completely in water.

<h3>What Causes Potassium to Explode in Water?</h3>

Chemists have long believed that throwing a lump of alkali metal into water, a time-honored technique still conducted by some lecturers and many chemical thrill seekers, generates an explosion because the metal dissolves, releasing high heat and transferring electrons to the water. The dissolving step also produces steam and makes hydroxide ions and hydrogen, which can be burnt to increase the process's energy.

They understood that the steam and hydrogen produced early in the reaction should form a buffer layer over the metal surface, preventing water from reacting further.

learn more about Potassium  refer

brainly.com/question/20306187

#SPJ4

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14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.
ValentinkaMS [17]

The correct answer is <em>B. a Salt </em><em>because The reaction of an acid and a base is called a neutralization reaction because the properties of both the acid and base are diminished or neutralized when they react. A neutralization reaction is a reaction of an acid with a base in aqueous solution to produce water and a salt, as shown by the following equation:</em>

<em>acid + base → salt + water</em>

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6 0
3 years ago
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4 0
3 years ago
Elements with great electron affinities (large negative values) often have
Svet_ta [14]

Answer:

3. small sizes and high ionization energies.

Explanation:

Hello,

Ionization energies are always related with the formation of positive ions. On the other hand, electron affinities are the negative ion equivalent, and their use is almost always confined to elements in groups 6 and 7 of the Periodic Table

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7 0
3 years ago
What is the total number of sublevels in the fourth principal energy level
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8 0
4 years ago
Calculate the ph of the resulting solution if 27.0 ml of 0.270 m hcl(aq is added to 37.0 ml of 0.270 m naoh(aq
bearhunter [10]
The reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
for neutralisation, H⁺ ions react with an equivalent amount of OH⁻ ions.
Number of NaOH moles reacted = 0.270 M/1000 mL/L x 37 mL = 0.00999 mol
number of HCl moles reacted = 0.270 M/1000 mL x 27 mL = 0.00729 mol
HCl reacts with NaOH in 1:1 molar ratio
Number of excess NaOH moles remaining - 0.00999 - 0.00729 = 0.0027 mol
total volume of solution = 37 mL + 27 mL = 64 mL = 0.064 L
Since there's excess OH⁻ ions, we can calculate pOH value first 
pOH = - log [OH⁻]
[OH⁻] = 0.0027 mol / 0.064 L = 0.042 mol/L
pOH = -log(0.042 M)
pOH = 1.37
by knowing pOH we can calculate pH using the following equation;
pH + pOH = 14
pH = 14 - 1.37
pH = 12.63
3 0
3 years ago
Read 2 more answers
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