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Free_Kalibri [48]
3 years ago
7

The first excited vibrational energy level of diatomic chlo- rine (Cl2) is 558 cm^-1 above the ground state. Wave- numbers, the

units in which vibrational frequencies are usually recorded, are effectively units of energy, with 1 cm ^-1 = 1.986445 X 10^-23 J. If every vibrational energy level is equally spaced, and has a degeneracy of 1, sum over the lowest 4 vibrational levels to obtain a vibrational partition function for chlorine.
Required:
Determine the populations of each of the four levels at 298 K and the average molar vibrational energy (Em.vib) for chlorine at 298 K.
Chemistry
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

The answer is "0.0000190 and 2.7 J".

Explanation:

\to P_4=\frac{e^{-\beta}(4+\frac{1}{2}) hev}{2vb}\\\\

         =\frac{e^{-9(1.35)}}{0.278v}\\\\=\frac{e^{-12.5}}{0.278}\\\\=\frac{0.000005285}{0.278}\\\\=0.0000190

Given:

h=6.626 \times 10^{-34}\\\\c=3\times 10^{10}\\\\v=558\ cm^{-1}\\\\K=1.38 \times 10^{-23}\\\\ T=298\\\\

E=\frac{hcv}{KT}\\\\

by putting the value into the above formula so, the value is 2.7 J  

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Dmitriy789 [7]

Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value

<span> The half-life for the chemical reaction is 29,2 s and is independent of initial concentration.
c</span>₀ - initial concentration the reactant.

c - concentration of the reactant remaining at time.

t = 29,2 s.<span>
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s</span> = 0,0237 1/s.<span>
ln(c/c</span>₀) = -k·t₁.<span>
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t₁ = 116,8 s.

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3 years ago
Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
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1) Ca: [Ar]4s²
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Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

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5 0
3 years ago
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