Question

Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers, and the other has white, terminal flowers; all F₁ individuals have red, axial flowers. The genes for flower color and location assort independently. Among the F₂ offspring, what is the probability of producing plants with white axial flowers? (A) 9 / 16 (B) 1 / 16 (C) 3 / 16 (D) 1 / 4

Answer 1

The probability of producing plants with white axial flowers is 1/16.

The given question is based on the law of independent assortment.There are two parents out of which one has red, axial flowers (RY) and the other one has white, terminal flowers (ry).

In F1 generation, all individuals have red, axial flowers which is RrYy which results in the formation of 8 gametes which is 4 from each parent. When these gametes are crossed with each other individually using a punett square, it results in the formation of 16 offspring out of which only one offspring has white terminal flowers.

Thus, the probability of producing plants with white axial flowers is 1/16.

To know more about independent assortment:

brainly.com/question/12338476

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