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exis [7]
1 year ago
10

Write a function g whose graph represents a reflection in the y-axis of the graph of f(x)=−3+|x−11|.

Mathematics
1 answer:
Jet001 [13]1 year ago
6 0

The function g whose graph represents a reflection in the y-axis of the graph of f(x)=−3+|x−11| is; g(x) = x + 8

<h3>How to solve transformation problems?</h3>

Transformations are used to change the position of a function from one point to another.

Now, we are given the function as;

f(x) = -3 + |x - 11|

To reflect the function above across the y-axis, we will make use of the following transformation rule: (x, y) → (-x, y)

Thus, since we are given f(x) = -3 + |x - 11|, applying the transformation rule above gives us;

f(-x) = -3 + |-1(x - 11)|

Removing the absolute sign gives us;

f(-x) = -3 + x + 11

f(-x) = x + 8

Thus, the function g whose graph represents a reflection in the y-axis of the graph of f(x)=−3+|x−11| is; g(x) = x + 8

Read more about Transformations at; brainly.com/question/4289712

#SPJ1

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Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s
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Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

No-show rate of 10%.

This means that p = 0.1

Four travelers who have made hotel reservations in this study.

This means that n = 4

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561

P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

X = 0 has the highest probability, which means that 0 is the most likely value for X.

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Answer:

Step-by-step explanation:

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(8/9)^2 is 64/81. Exponent is 2. Hope this help
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