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LenaWriter [7]
3 years ago
15

Two numbers have difference of 0.7 and a sum of 1. What are the numbers?

Mathematics
1 answer:
algol [13]3 years ago
4 0
We can solve this by setting up 2 equations. We can use any letters like. For now, I'll use x and y.
So now we know that    x - y = 0.7   and    x + y = 1.
Now we can eliminate one of the letters by adding or subtracting one equation from the other. I am going to eliminate y by adding the two together (the y and the -y cancel).
This gives us   2x = 1.7,    and so x = 1.7 ÷ 2 = 0.85
Finally, we can substitute x for 0.85 back into one of the original equations to figure out what y equals. I'm going to use   x + y = 1.
So now we have    0.85 + y = 1,    so y = 1 - 0.85 = 0.15

The numbers, therefore, are 0.85 and 0.15 (you can check by using the other equation).

Hope this helps!
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MatroZZZ [7]
The answer is 76
If this answered help you then please consider marking it as brainliest to help me level up to expert
8 0
3 years ago
Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
3 years ago
Please help me with this question please
Neko [114]

Answer:

I think it is B. It does not look comparable.

7 0
3 years ago
Read 2 more answers
The bottom of a rectangular swimming pool has an area of 150 square meters and a perimeter of 50 meters. What are the dimensions
AysviL [449]

The  dimensions of the pool is 15m by10m

<h3>Area and perimeter of rectangle</h3>

A pool is rectangular in nature. If a rectangular swimming pool has an area of 150 square meters and a perimeter of 50 meters, then;

lw = 150

2(l+w) = 50

l + w = 25

where

l is the length

w is the width

From the equation 3

l = 25 - w

Substitute into 1

(25-w)w = 150
25w-w² = 150
w²-25w+150 = 0
w²-10w-15w+150 = 0

Factor

w(w-10)-15(w-10) = 0

w = 10 and 15

l = 150/10 = 15

Hence the  dimensions of the pool is 15m by10m

Learn more on dimension here: brainly.com/question/26740257

#SPJ1

7 0
1 year ago
How do I make a the subject?<br><br> S= a/4 + 8u
Crazy boy [7]
S= a/4 + 8u

S - 8u = a/4 (First you subtract 8u from both sides)

4(S - 8u) = a ( Then you multiply both sides by 4)

Final answer:
4(S - 8u) = a
8 0
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