<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
side note: multiplying by the LCD of both sides is just to get rid of the denominators
Answer:
go down then go right
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
For lines to be parallel alternate interior angles should be equal
Angle GHD=180-angle FHD
=180-115 = 65°
Therefore angle AGH = angle GHD
So lines are parallel
The surface area of the square pyramid is: 451 cm²
The lateral surface area of the square pyramid = 330 cm²
<h3>What is the Lateral Surface Area and Surface Area of a Square Pyramid?</h3>
Surface area = a² + 2al, where a is the base edge and l is the slant height.
Lateral Surface Area = 2al.
Given the following:
Surface area = a² + 2al = 11² + 2(11)(15)
Surface area = 451 cm²
Lateral Surface Area = 2al = 2(11)(15)
Lateral Surface Area = 330 cm²
Learn more about square pyramid on:
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