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True [87]
1 year ago
10

Which pair of angle measures is supplementary?

Mathematics
1 answer:
AURORKA [14]1 year ago
4 0

Answer:

B) :) I hope this helps!!!!!!!

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Identify the diameter using the following radius: 16 ft.
Firlakuza [10]
B this answer is 4 it’s correct
7 0
3 years ago
Which is the polynomial function of lowest degree with leading coefficient of 4 and roots 7 and 3?
NISA [10]

Answer:

f(x) = 4x² - 40x + 84

Step-by-step explanation:

4(x - 7)(x - 3) = 0

4(x² - 3x - 7x + 21) = 0

4(x² - 10x + 21) = 0

4x² - 40x + 84 = 0

3 0
3 years ago
Aliza plays basketball every Tuesday and
Lemur [1.5K]

Answer:

4 days

Step-by-step explanation:

June starts on Monday

for 30days we have 4 weeks starting from Monday to Sunday and extra 2 days which are Monday and Tuesday

so we have 5 mondays and tuesdays

4 wed, thu, fri, sat, sun

Aliza played piano on june1 monday

So aliza played basketball on 5 tues + 4 thurs = 9 days

for calculating both basketball and paino

piano day should be on tuesday or thursday

from the below picture u can see pink dots are piano days

and yellow circles are both piano and basketball days

so on alternate weeks they are coinciding

so there are 4 days

3 0
2 years ago
Sold 72 books, if ratio of books to bookmarks sols was 9:2, how many bookmarks sold?
REY [17]

16 book marks has been sold

5 0
2 years ago
Read 2 more answers
What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
2 years ago
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