Answer:
ΔCOG
Step-by-step explanation:
A is reflected in line DB to C.
O is on line DB, so is reflected to itself.
F is reflected in line DB to G.
Hence ΔAOF is reflected in line DB to ΔCOG.
Hello,
Part A:
f(2)=4*2²=16
f(1)=4*2^1=8
2-1=1
(f(2)-f(1))/(2-1)=(16-8)/1=8 ; r_1=8
f(3)=4*2^3=32
f(4)=4*2^4=64
(f(4)-f(3))/(4-3)=(64-32)/1=32 ; r_2=32
Part B:
r_2=32=4*8=4*r_1
Explainations:
(4*2^2-4*2^1)/(2-1)=4*2^1(2-1)=4*2
(4*2^4-4*2^3)/(4-3)=4*2^3*(2-1)=4*8=(4*2)*4
Answer:
30 ft
Step-by-step explanation:
