Answer:
The equation of a right triangle is given by a2 + b2 = c2, where either a or b is the height and base of the triangle and c is the hypotenuse. Using the Pythagorean Theorem, finding the missing side of a triangle is pretty simple and easy. The two special right triangles include: 45°; 45°; 90° Triangle.
a correct answer that guy ☝ is rude can i get brainliest for answering
Oh ok. So I think that x is 83. Because I did this 630-100-121-106-112-108=83. And then I did 630/6 and got 105 and thats the mean.
Answer:
77°, 103°
Step-by-step explanation:
x=103°
- z=x=103°
- y=180°-x=180°-103°=77°
-----------
∠5= 42°
∠3= 180°-42°=138°
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
Answer:
because you divide them by two
Step-by-step explanation:
