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1 year ago

6-3/4x+1/3=1/2x+5 what number can be used to get rid of all fractions

Mathematics

1 answer:

Yanka [14]1 year ago

7 0

The number can be used to get rid of all fractions is 12

<h3>What number can be used to get rid of all fractions?</h3>

The equation is given as:

6 - 3/4x + 1/3 = 1/2x + 5

The denominator of the fractions are:

4, 3 and 2

The LCM of 4, 3 and 2 is 12

So, we have:

12 * [6 - 3/4x + 1/3] = 12 * [1/2x + 5]

Evaluate the products

72 - 9x + 12 = 6x + 60

Hence, the number can be used to get rid of all fractions is 12

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Find Distance (4,6) (-4,-3)

vampirchik [111]

Answer:

$\sqrt{145}$

Step-by-step explanation:

The distance formula states that the distance between two points $(a,b)$ and $(c,d)$ is $\sqrt{(a-c)^2+(b-d)^2}$ .

The two points we have are $(4,6)$ and $(-4,-3)$ . Plugging these numbers into the distance formula, we have

$\sqrt{(4-(-4))^2+(6-(-3))^2$ .

Simplifying with order of operations, first using the distributive property, gives

$\sqrt{(4+4)^2+(6+3)^2$ .

Squaring and adding gives

$\sqrt{(4+4)^2+(6+3)^2}=\sqrt{8^2+9^2}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\sqrt{64+81}\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~=\boxed{\sqrt{145}},$

which is the answer in simplest form. This also rounds to about 12.04.

7 0

2 years ago

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}
$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

2 years ago

Let f(x)=4x+7 and g(x)=3x-5. Find (g o f)(-4)<br><br> A)-32<br> B)-61<br> C)-64<br> D)-9

olya-2409 [2.1K]

Answer for this question is -32

5 0

2 years ago

Help Me! ASAP! Determine whether each equation has no solution, one solution or infinitely many solutions. Choose No Solution, O

ladessa [460]

Answer:

Step-by-step explanation:

(1). One solution

(2). Infinitely Many Solutions

(3). One solution

(4). No Solution

7 0

2 years ago

Read 2 more answers

-2/3 x -9/8 x -4/5 x -1

Lerok [7]

Answer: 0.6

Step-by-step explanation: First, you want so seperate the equations in parenthesis to make solving the equation easier.

(-2/3x-9/8x )-(4/5x)-(1)

So (-2/3x-9/8x) equals -11/24x

And -11/24x-4/5x equals -151/120x

So -151/120x-1 ends up being 0.6.

5 0

2 years ago