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kvv77 [185]
3 years ago
9

A dust bunny gathers dust at a rate of 11% per week. The dust bunny, Alfred, originally weighed 0.7 ounces. Write an equation th

at represents the weight of Alfred at a given time. Use t for weeks and w for the weight of the dust bunny. Using this equation, what is the weight of the dust bunny after 7 weeks?
Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0
Alfred is 0.7 ounces at the beginning.
After one week had passed, he is 11% larger. 0.7 * 1.11
After two weeks, the dust bunny's size is once again 11% larger.
0.7 * 1.11 * 1.11, or 0.7 * 1.11².

From here you can see that each week the dust bunny's size multiplies by 1.11. (1 whole plus 11 percent) How many times it is multiplied can be expressed with exponents.

w = 0.7*1.11^{x}
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Suppose you are determining the growth rate of two species of plants. Species A is 25 cm tall and grows 3 cm per month. Species
jarptica [38.1K]
If the growth rate is a constant, we can model it using a linear equation:

y = b + ax

where b = initial value, a = growth rate.
In this case, x = m = number of months.

Let's find the equation for the growth of each species.

Species A:
Initial height = b = 25 cm
Growth rate = a = 3 cm per month
So its height can be modeled by H(m) = 25 + 3m

Species B:
Initial height = b = 10 cm
Growth rate = a = 8 cm per month
So its height can be modeled by H(m) = 10 + 8m

Thus the answer is A: H(m) = 25 + 3m and B: H(m) = 10 + 8m.
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3 years ago
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4. (4x – 2y) – (2x – 6y)
rodikova [14]

Answer:

(4x -2y)-( 2x-6y) = 2x-(-4y)

Step-by-step explanation:

only the same sign can be together. so you take the x first 4-2 which is 2x then you take the y signs 2-6 which would be -4 the full equation becomes 2x-(-4)

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3 years ago
Which answer choice
joja [24]

Answer: b

Step-by-step explanation: I did this on a test before

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2 years ago
A rectangular storage container with an open top is to have a volume of 24 cubic meters. The length of its base is twice the wid
Mariana [72]

Answer:

419.25

Step-by-step explanation:

The calculation of the cost of materials for the cheapest such container is shown below:-

We assume

Width = x

Length = 2x

Height = h

where, length = 2 \times width

Base area = lb

= 2x^2

Side area = 2lh + 2bh

= 2(2x)h + 2(x)h

= 4xh + 2xh

Volume = 24 which is lbh = 24

h = \frac{24}{2x^2} \\\\ h = \frac{12}{x^2}

Now, cost is

= 13(2x^2) + 9(4xh + 2xh)\\\\ = 13(2x^2) + 9(4x + 2x)\times \frac{12}{x^2} \\\\ = 26x^2 + \frac{648}{x}

now we have to minimize C(x)

So, we need to compute the C'(x)

= 52x - \frac{648}{x^2}

C"(x)  = 52x - \frac{1,296}{x^3}

now for the critical points, we will solve the equation C'(x) = 0

= 52x - \frac{648}{x^2} = 0\\\\ x = \frac{648}{52}^{\frac{1}{3}}

C" = ((\frac{648}{52} ^{\frac{1}{3} } = 52 + \frac{1296}{(\frac{648}{52})^\frac{1}{3} )^3}\\\\ = 52 + \frac{1296}{\frac{648}{52} } >0

So, x is a point of minima that is

= (\frac{648}{52} )^\frac{1}{3}

Now, Base material cost is

= 13(2x^2)\\\\ = 26(\frac{648}{52} )^\frac{2}{3}

= 139.75

Side material cost is

= \frac{648}{x} \\\\ = \frac{648}{(\frac{648}{52})^\frac{1}{3}  }

= 279.50

and finally

Total cost is

= 139.75 + 279.50

= 419.25

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Answer:

A.

Step-by-step explanation:

The first number is 2, so 2 must be plotted on the X radius (because it goes by X first). B plots X on the Y axis so therefore, by process of elimination, A is the answer.

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3 years ago
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