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3 years ago

13

Which fraction, decimal number, and percent are equivalent?

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

A. 2/5, 0.40, 40%

Step-by-step explanation:

To turn a fractions into a decimal divided the numerator by the denominator. 2/5=0.40.

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Are there any perpendicular lines in the letter L? i also need this now

Nana76 [90]

Answer:

wow there buddy

Step-by-step explanation:

6 0

3 years ago

Osian was 1.5 m tall. In the last couple of years,his height has increased by 20%

3241004551 [841]

For this case we must find the current height of Osian. For this, we use the following rule of three:

1.5 m ----------------> 100%

x -----------------------> 120%

From here, we clear the value of x.

We have then:

$x = \frac {120} {100} (1.5)\\x = 1.8 m$

Answer:

The current height of Osian is given by:

$x = 1.8 m$

4 0

3 years ago

I'm stuck on this question, any ideas? thanks

True [87]

Answer:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}=-1/36$

Step-by-step explanation:

So we have the limit:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}$

Let's remove the fractions in the denominator by multiplying both layers by (6+x)(6). So:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}\cdot (\frac{(6+x)(6)}{(6+x)(6)})$

Distribute:

$=\lim_{x \to 0} \frac{(6)-(6+x)}{x(6+x)(6)}$

Simplify the numerator:

$=\lim_{x \to 0} \frac{6-6-x}{x(6+x)(6)}\\=\lim_{x \to 0} \frac{-x}{x(6+x)(6)}$

Both the numerator and the denominator have an x. Cancel:

$=\lim_{x \to 0} \frac{-1}{(6+x)(6)}$

Direct substitution:

$= \frac{-1}{(6+0)(6)}$

Simplify:

$=-1/36$

And that's our answer.

And we're done!

8 0

3 years ago

Read 2 more answers

An equation of the circle whose center is the origin and

tankabanditka [31]

Answer:

$\fbox{\begin{minipage}{10em}Option C is correct\end{minipage}}$

Explanation:

A circle whose center is $(a, b)$ and radius $r$ , has equation:

$(x - a)^{2} + (y - b)^{2} = r^{2}$

The center of circle is given as origin $(0, 0)$ , therefore:

$a = 0\\b = 0$

This circle passes $(3, 0)$ , then the radius of circle is the distance $(d)$ between origin $(0, 0)$ and $(3, 0)$

$d = \sqrt{(0 - 3)^{2} + (0 - 0)^{2} } = \sqrt{3^{2} } = 3$

=> $r = d = 3$

Substitute $a$ , $b$ , and $r$ back into original equation:

$(x - 0)^{2} + (y - 0)^{2} = 3^{2}$

or

$x^{2} + y^{2} = 9$

Hope this helps!

:)

3 0

3 years ago

What is the value for f (x) = 4^2x -100 when x = 2

Wewaii [24]

X=2
So,
=4^2×2 -100
=4^4-100
=256-100
=56

5 0

3 years ago