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Luden [163]
3 years ago
13

Which fraction, decimal number, and percent are equivalent?

Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

A. 2/5, 0.40, 40%

Step-by-step explanation:

To turn a fractions into a decimal divided the numerator by the denominator. 2/5=0.40.

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Are there any perpendicular lines in the letter L? i also need this now
Nana76 [90]

Answer:

wow there buddy

Step-by-step explanation:

6 0
3 years ago
Osian was 1.5 m tall. In the last couple of years,his height has increased by 20%
3241004551 [841]

For this case we must find the current height of Osian. For this, we use the following rule of three:

1.5 m ----------------> 100%

x -----------------------> 120%

From here, we clear the value of x.

We have then:

x = \frac {120} {100} (1.5)\\x = 1.8 m

Answer:

The current height of Osian is given by:

x = 1.8 m

4 0
3 years ago
I'm stuck on this question, any ideas? thanks
True [87]

Answer:

\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}=-1/36

Step-by-step explanation:

So we have the limit:

\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}

Let's remove the fractions in the denominator by multiplying both layers by (6+x)(6). So:

\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}\cdot (\frac{(6+x)(6)}{(6+x)(6)})

Distribute:

=\lim_{x \to 0} \frac{(6)-(6+x)}{x(6+x)(6)}

Simplify the numerator:

=\lim_{x \to 0} \frac{6-6-x}{x(6+x)(6)}\\=\lim_{x \to 0} \frac{-x}{x(6+x)(6)}

Both the numerator and the denominator have an x. Cancel:

=\lim_{x \to 0} \frac{-1}{(6+x)(6)}

Direct substitution:

= \frac{-1}{(6+0)(6)}

Simplify:

=-1/36

And that's our answer.

And we're done!

8 0
3 years ago
Read 2 more answers
An equation of the circle whose center is the origin and
tankabanditka [31]

Answer:

\fbox{\begin{minipage}{10em}Option C is correct\end{minipage}}

Explanation:

A circle whose center is (a, b) and radius r, has equation:

(x - a)^{2} + (y - b)^{2} = r^{2}

The center of circle is  given as origin (0, 0), therefore:

a = 0\\b = 0

This circle passes (3, 0), then the radius of circle is the distance (d) between origin (0, 0) and (3, 0)

d = \sqrt{(0 - 3)^{2} + (0 - 0)^{2} } = \sqrt{3^{2} } = 3

=> r = d = 3

Substitute a, b, and r back into original equation:

(x - 0)^{2} + (y - 0)^{2}  = 3^{2}

or

x^{2} + y^{2} = 9

Hope this helps!

:)

3 0
3 years ago
What is the value for f (x) = 4^2x -100 when x = 2
Wewaii [24]
X=2
So,
=4^2×2 -100
=4^4-100
=256-100
=56
5 0
3 years ago
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