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Aneli [31]
3 years ago
13

Solve x2 − 8x + 15 < 0.

Mathematics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Given the quadratic inequality we are to find the interval of x

x² − 8x + 15 < 0

Factorize

x²-3x-5x+15<0

x(x-3)-5(x-3)<0

(x-3)(x-5)<0

(x-3)<0 and x-5<0

if x+3<0

x<-3

If x-5<0

x<5

Hence the solution yo the quadratic inequality are x<3 and x<5

Hence

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A dice has 6 numbers; 1,2,3,4,5,6

3 of which are odd numbers

which means:

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Which phrase best describes the translation from the group y=2x^2 to the graph of y= 2x^2 +5
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7 0
3 years ago
3x^2 -5x -2=0
Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

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x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

6 0
3 years ago
Read 2 more answers
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